Y=-16x^2-4x+1482

Solution for Y=-16x^2-4x+1482 equation:

=-16Y^2-4Y+1482

We move all terms to the left:

-(-16Y^2-4Y+1482)=0

We get rid of parentheses

16Y^2+4Y-1482=0

a = 16; b = 4; c = -1482;
Δ = b2-4ac
Δ = 42-4·16·(-1482)
Δ = 94864
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{94864}=308$
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-308}{2*16}=\frac{-312}{32}
=-9+3/4
$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+308}{2*16}=\frac{304}{32}
=9+1/2
$